2log[5](x+1)=2

Solution for 2log[5](x+1)=2 equation:

Simplifying
2log[5](x + 1) = 2

Reorder the terms:
2glo * 5(1 + x) = 2

Reorder the terms for easier multiplication:
2 * 5glo(1 + x) = 2

Multiply 2 * 5
10glo(1 + x) = 2
(1 * 10glo + x * 10glo) = 2
(10glo + 10glox) = 2

Solving
10glo + 10glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + 10glo + 10glox = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 10glo + 10glox = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-1 + 5glo + 5glox) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(-1 + 5glo + 5glox)' equal to zero and attempt to solve:

Simplifying
-1 + 5glo + 5glox = 0

Solving
-1 + 5glo + 5glox = 0

Move all terms containing g to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 5glo + 1 + 5glox = 0 + 1

Reorder the terms:
-1 + 1 + 5glo + 5glox = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 5glo + 5glox = 0 + 1
5glo + 5glox = 0 + 1

Combine like terms: 0 + 1 = 1
5glo + 5glox = 1

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.